Food Test for Vitamin C (DCPIP Test)
The DCPIP test detects vitamin C in food. A food extract is added drop by drop to blue DCPIP solution; decolourisation of the DCPIP shows vitamin C is present.
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Aim
To test a food sample for the presence of vitamin C using DCPIP solution, and to compare the vitamin C content of different food samples.
What it tests for
The DCPIP test detects vitamin C (ascorbic acid) in food. DCPIP (2,6-dichlorophenolindophenol) is a blue dye that is reduced and loses its colour when it reacts with vitamin C, which is a reducing agent.
The number of drops of food extract needed to decolourise a fixed amount of DCPIP gives a rough, semi-quantitative comparison of vitamin C content between samples.
Variables
- Manipulated variable: the type of food extract tested, for example orange juice, lemon juice, and guava juice.
- Responding variable: the number of drops of food extract needed to decolourise a fixed volume of DCPIP solution.
- Controlled variables: the volume and concentration of DCPIP solution, the size of each drop, and the temperature of the extract.
Materials and apparatus
- Food extracts or fruit juices to be tested
- 0.1% DCPIP solution (blue)
- A standard vitamin C (ascorbic acid) solution for comparison
- Test tubes and a test-tube rack
- A graduated dropper or syringe, and a measuring cylinder
- A white tile or white paper as a background to judge the colour
- A filter funnel and filter paper for preparing extracts
Reagent and method
- Prepare a food extract, such as fruit juice, by squeezing or crushing the food and filtering if necessary.
- Place about 2 cm3 of blue DCPIP solution into a clean test tube.
- Using a dropper, add the food extract to the DCPIP solution one drop at a time.
- Shake or swirl the test tube gently after each drop.
- Continue adding drops and count them until the blue colour of the DCPIP just disappears.
Positive result
A positive result is shown when the blue DCPIP solution becomes colourless (decolourised) after a number of drops of food extract are added. Fewer drops needed to decolourise the DCPIP indicates a higher concentration of vitamin C in the food extract, while more drops needed indicates a lower concentration.
Expected results
The drop count for each extract can be tabulated and used to rank the samples by vitamin C content.
| Food extract | Drops needed to decolourise DCPIP | Inference |
|---|---|---|
| Guava juice | Few drops | High vitamin C content |
| Orange juice | More drops | Moderate vitamin C content |
| Boiled orange juice | Most drops, or no decolourisation | Low vitamin C content (heat destroys vitamin C) |
Inference and conclusion
DCPIP is decolourised because vitamin C is a reducing agent that reduces the blue dye to a colourless form. The fewer drops of extract needed to decolourise a fixed volume of DCPIP, the higher the concentration of vitamin C in that extract.
Comparing the drop counts therefore ranks the samples by vitamin C content, as long as the same volume and concentration of DCPIP is used each time. Because vitamin C is destroyed by heat, a boiled sample needs more drops than a fresh one, which shows why fresh fruit and gentle cooking preserve more vitamin C.
Paper 3-style questions
Question 1 (hypothesis). A student compares fresh orange juice with orange juice that has been boiled. State a suitable hypothesis.
Model answer. Fresh orange juice contains more vitamin C than boiled orange juice, so it needs fewer drops to decolourise the same volume of DCPIP.
Question 2 (variables). State the manipulated, responding and one controlled variable for this comparison. Model answer. Manipulated variable: whether the juice is fresh or boiled.
Responding variable: the number of drops needed to decolourise the DCPIP. Controlled variable: the volume of DCPIP solution (also its concentration, the drop size, and the temperature at testing).
Question 3 (tabulation and graph). The student tests four fruits. How should the results be recorded and displayed?
Model answer. Record the drops needed for each fruit in a table, then draw a bar chart of drops against fruit; a shorter bar means higher vitamin C content.
Question 4 (inference). Fresh juice needed 8 drops and boiled juice needed 20 drops to decolourise the DCPIP. What can you infer?
Model answer. The fresh juice contains more vitamin C than the boiled juice, because it needed fewer drops; boiling has destroyed some of the vitamin C. This supports the hypothesis.
Safety
- Wear safety goggles, because DCPIP solution and acidic fruit juices can irritate the eyes.
- Add the extract with a clean dropper and avoid touching your mouth with it.
- Handle glassware carefully to avoid breakage, and clean up spills promptly.
- Wash your hands after handling the reagents and dispose of used solutions as directed.
Common mistakes
Source:SRC-DSKP-EN
Frequently asked questions
What happens to DCPIP solution when vitamin C is present?
How does the DCPIP test compare vitamin C content between two foods?
Why must the food extract be added drop by drop?
Why does boiled juice need more drops than fresh juice?
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