Sex-Linked Inheritance
Sex-linked inheritance refers to genes carried on the sex chromosomes, usually the X chromosome. Because males have only one X chromosome, a single recessive allele on it is enough to produce the condition, making males more often affected than females.
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What sex-linked means
Most genes discussed in genetics are carried on autosomes (the 22 non-sex chromosome pairs) and are inherited without reference to sex. Sex-linked genes are instead carried on a sex chromosome, almost always the X chromosome, since the Y chromosome carries very few genes.
Because the sex chromosomes an individual has depends on their sex, so does their pattern of inheriting X-linked genes.
Notation for X-linked alleles
X-linked alleles are written as a superscript on the X chromosome itself, e.g. XH for a normal allele and Xh for a recessive allele. A female genotype always has two X's (XH XH, XH Xh, or Xh Xh).
A male genotype has one X and one Y (XH Y or Xh Y), the Y carries no matching allele for this gene.
Why males are more often affected
A female needs two copies of a recessive X-linked allele (Xh Xh) to show the recessive condition, because a single XH allele is enough to mask it. A male, however, has only one X chromosome, so a single Xh allele is enough to produce the recessive phenotype, there is no second X chromosome to mask it.
This is why X-linked recessive conditions such as colour blindness and haemophilia occur far more often in males than in females.
Carriers
A female with genotype XH Xh is called a carrier. She does not show the recessive condition herself, because the dominant XH allele masks it, but she can pass the Xh allele on to her children, who may then be affected depending on which X chromosome and which parent's gamete they inherit.
Worked problem 1, easy: carrier mother x normal father
Question. Colour blindness is X-linked recessive: XB is the normal allele and Xb causes colour blindness. A carrier mother (XB Xb) has children with a father of normal vision (XB Y).
Draw the Punnett square and describe the sons and daughters.
Model answer. The mother forms XB and Xb eggs; the father forms XB and Y sperm. All daughters receive XB from the father, so none is colour-blind, but half are carriers (XB Xb).
Sons receive only the mother's X, so they are 1 normal (XB Y) : 1 colour-blind (Xb Y).
| XB (egg) | Xb (egg) | |
|---|---|---|
| XB (sperm) | XB XB (normal daughter) | XB Xb (carrier daughter) |
| Y (sperm) | XB Y (normal son) | Xb Y (colour-blind son) |
Worked problem 2, medium: carrier mother x colour-blind father
Question. A carrier mother (XB Xb) has children with a colour-blind father (Xb Y). Predict the genotypes and phenotypes of the daughters and the sons.
Model answer. The mother forms XB and Xb eggs; the father forms Xb and Y sperm. Daughters are 1 carrier (XB Xb) : 1 colour-blind (Xb Xb), here a daughter can be colour-blind because she can receive Xb from both parents.
Sons are 1 normal (XB Y) : 1 colour-blind (Xb Y). Overall, half of all the children are colour-blind.
| XB (egg) | Xb (egg) | |
|---|---|---|
| Xb (sperm) | XB Xb (carrier daughter) | Xb Xb (colour-blind daughter) |
| Y (sperm) | XB Y (normal son) | Xb Y (colour-blind son) |
Worked problem 3, SPM-level: deducing a genotype
Question. A woman with normal colour vision, whose father was colour-blind, marries a colour-blind man. (a) Work out the woman's genotype.
(b) Draw the cross and state the proportion of their children, and of which sex, expected to be colour-blind.
Model answer. (a) The woman has normal vision, so she has at least one XB, but her father was colour-blind (Xb Y) and passed his single Xb to her; therefore she is a carrier, XB Xb. (b) The cross is XB Xb (mother) x Xb Y (father).
As the grid shows, daughters are 1 carrier (XB Xb) : 1 colour-blind (Xb Xb), and sons are 1 normal (XB Y) : 1 colour-blind (Xb Y). So half of the children are colour-blind, made up of colour-blind daughters and colour-blind sons in equal numbers.
| XB (egg) | Xb (egg) | |
|---|---|---|
| Xb (sperm) | XB Xb (carrier daughter) | Xb Xb (colour-blind daughter) |
| Y (sperm) | XB Y (normal son) | Xb Y (colour-blind son) |
Practice problems
- 1. A man with normal colour vision (XB Y) marries a carrier woman (XB Xb). What fraction of their sons is expected to be colour-blind?
- 2. Can a colour-blind daughter be born to a father who has normal colour vision? Explain your answer.
- 3. A woman is a carrier for haemophilia (XH Xh) and her husband does not have haemophilia (XH Y). State the probability that a son has haemophilia.
Practice answers
How it is examined
SPM questions typically use superscript notation on X and Y, ask you to identify carriers, and require a Punnett square to predict the genotypes and phenotypes of children from parents with given X-linked genotypes.
Common mistakes
Source:SRC-DSKP-EN
Frequently asked questions
What does sex-linked inheritance mean?
Why are males more often affected by X-linked recessive conditions?
What is a carrier in sex-linked inheritance?
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